2sin^2(2x)+6cosx=2

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Solution for 2sin^2(2x)+6cosx=2 equation:


Simplifying
2sin2(2x) + 6cosx = 2

Remove parenthesis around (2x)
2in2s * 2x + 6cosx = 2

Reorder the terms for easier multiplication:
2 * 2in2s * x + 6cosx = 2

Multiply 2 * 2
4in2s * x + 6cosx = 2

Multiply in2s * x
4in2sx + 6cosx = 2

Reorder the terms:
6cosx + 4in2sx = 2

Solving
6cosx + 4in2sx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4in2sx' to each side of the equation.
6cosx + 4in2sx + -4in2sx = 2 + -4in2sx

Combine like terms: 4in2sx + -4in2sx = 0
6cosx + 0 = 2 + -4in2sx
6cosx = 2 + -4in2sx

Divide each side by '6osx'.
c = 0.3333333333o-1s-1x-1 + -0.6666666667in2o-1

Simplifying
c = 0.3333333333o-1s-1x-1 + -0.6666666667in2o-1

Reorder the terms:
c = -0.6666666667in2o-1 + 0.3333333333o-1s-1x-1

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